Question OT 20 Map sapling learning Two skydivers are holding on to each other w

Question

Question OT 20 Map sapling learning Two skydivers are holding on to each other while falling straight down at a common terminal speed of 58.30 m/s. Suddenly, they push away from each other. Immediately after separation, the first skvdiver (who has a mass of 89.30 kg) has the following velocity components (with "straight down" corresponding to the positive zaxis): 3.750 m/s vir 4.930 m/s 58.30 m/s 1,2 What are the x- and y components of the velocity of the second skydiver, whose mass is 63.20 kg, immediately after separation? Number 2x Number What is the change in kinetic energy of the system? Number Joules Previous Check Answer E Next Exit Hint

Explanation / Answer

u1z = u2z = 58 m/s, m1 =89.3 kg, m2 = 63.2 kg

v1x =4.93 m/s, v1y = 3.75 m/s, v1z =58.3 m/s

From conservation of momentum along x direction

m1u1x +m2u2x = m1v1x +mv2x

0 = (89.3*4.93)+(63.2*v2x)

v2x = -6.966 m/s

From conservation of momentum along y direction

m1u1y +m2u2y = m1v1y +mv2y

0 = (89.3*3.75)+(63.2*v2y)

v2y = -5.299 m/s

From conservation of momentum along z direction

m1u1z +m2u2z = m1v1z +mv2z

(89.3+63.2)58.3 = (89.3*58.3)+(63.2*v2z)

v2z = 58.3 m/s

(b) K1 - K2 = (1/2)(m1+m2)u^2 -(1/2)m1v1^2 -(1/2)m2v2^2

= (0.5(89.3+63.2)*58.3*58.3) -(0.5*89.3*(4.93^2+3.75^2+58.3^2) -(0.5*63.2*(6.966^2+5.299^2+57.576^2)

= 2.2*10^5 J

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