MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEXT Chapter 26, Problem

Question

MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEXT Chapter 26, Problem 058 Your answer is partially correct. Try again. Concept Simulation 26.4 provides the option of exploring the ray diagram that applies to this problem. The distance between an object and its image formed by a diverging lens is 5.10 cm. The focal length of the lens is-2.50 cm. Find (a) the image distance and (b) the object distance. Unitscm (a) Number (b) Number Click if you would like to Show Work for this question: Unitsl cm Open Show Work SHOW HINT Question Attempts: 2 of 5 usedSAVE FOR LATER S SUBMIT ANSWER Copyright © 2000-2016 by John Wiley & Sons, Inc. or related companies. All rights reserved

Explanation / Answer

x+x' =5.1 cm ,

x' = 5.1 - x

f =-2.5 cm

from lens formula (1/f) = (1/x)+(1/x')

-(1/2.5) = (1/x) +(1/(5.1-x))

(a) x =6.9377 cm

object is infront of lens , so object distance is positive

(b) x' = -1.837 cm

image is infront of lens , so image distance is negative

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