Mwww.physics.wisc.edu/unc × Mwww.physics.wisc.edu/unc × GOn A Frictionless woode
ID: 1489926 • Letter: M
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Mwww.physics.wisc.edu/unc × Mwww.physics.wisc.edu/unc × GOn A Frictionless wooder × Dwww.physics.wisc.edu/undergrads/courses/fall2015/201 /Final-Key.pdf :: Apps Physics Homework P Econ Homework D Math 234 Program ming Facebook Physics Syllabus M University of Wiscon eChegg 10. Two objects are connected by a light string passing over a light, frictionless pullev as shown in the figure below. The object of mass m-6.20 kg is released from rest at a height h above the table. When mi hits the table, the speed of block m2, which has a mass of 3.0kg, is measured to be 5.09 m/s. What is h? (hint: you can use Newton's 2 ad law, but an energy approach would be easier) a. 2.8 m b. 1.3 m c. 6.6 m d. 3.8 m e- none of above is within 5% from the correct answer 11. In the above setting, what is the maximum height above the table the mass m2 can reach? (hint: you need to sum up the height of m2 when mi hits the table, and the extra height m2 will fly after that) a. 4.5 m b. 2.3 m c. 5.1m d. 1.2 m physics.gif physics.png Show all downloa SLi 9:28 PM 12/19/2015Explanation / Answer
1.
use the law of conservation of energy to find the h.
[m1-m2]gh = 0.5[m1+m2]v2
[6.2-3.0]*9.8*h = 0.5[6.2+3.0]5.09^2
h = 3.8 m
2.
the vertical displacement is,
y = v2/2g = 5.09*5.09/2*9.8 = 1.32 m
hence, the maximum heght is,
hmax = 1.32 +3.8 = 5.1 m
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