A wrecking ball swings at the end of a 12 m cable on a verticals circular arc. A

Question

A wrecking ball swings at the end of a 12 m cable on a verticals circular arc. As the ball passes through its lowest point of the swing it has a speed of 5 m/s. What speed does the ball have when the cable makes an angle of 20 degrees relative to the vertical? A wrecking ball swings at the end of a 12 m cable on a verticals circular arc. As the ball passes through its lowest point of the swing it has a speed of 5 m/s. What speed does the ball have when the cable makes an angle of 20 degrees relative to the vertical?

Explanation / Answer

u = 5m/sL =12 m

cos(20) =x/L

x =Lcos(20)

h = L-Lcos(20) = 12 -12cos(20)

h = 0.7237 m

From conservation of energy

K1+U1 =K2+U2

(1/2) mu^2 +0 = (1/2)mv^2 +mgh

v^2 =u^2 -2gh = (5*5) -(2*9.8*0.7237)

v =3.29 m/s

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