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A helium balloon ride lifts up passengers in a basket. Assume the density of air

ID: 1484330 • Letter: A

Question

A helium balloon ride lifts up passengers in a basket. Assume the density of air is 1.28 kg/m3 and the density of helium in the balloon is 0.18 kg/m3. The radius of the balloon (when filled) is R = 5.1 m. The total mass of the empty balloon and basket is mb = 125 kg and the total volume is Vb = 0.064 m3. Assume the average person that gets into the balloon has a mass mp = 71 kg and volume Vp = 0.077 m3.

1)

What is the volume of helium in the balloon when fully inflated?
m3

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556

Computed value:

556

Submitted:

Wednesday, December 9 at 1:14 PM

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Correct!

2)

What is the magnitude of the force of gravity on the entire system (but with no people)? Include the mass of the balloon, basket, and helium.
N

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3)

What is the magnitude of the buoyant force on the entire system (but with no people)? Include the volume of the balloon, basket, and helium.
N

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4)

What is the magnitude of the force of gravity on each person?
N

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5)

What is the magnitude of the buoyant force on each person?
N

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6)

How many FULL people can the balloon lift up? (Your answer must be an integer.)
people

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(Survey Question)

7)

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Explanation / Answer

1) V = 4/3 pi r^3
V = 1.3333 * 3.141592 * 5.1 ^ 3
V = 555.65 m^3

2) Mass balloon = 125 kg
Mass Helium = d_Helium * Volume = 0.18 kg/m^3 * 555.65 = 100.01 kg
Total Mass =225.01 kg

Force = m*g
m =225.01
g = 9.81
F = m*g
F = 225.01 * 9.81
F = 2207.35 N

3) Mass of displaced volume of air. = d * V
d = 1.28 kg/m^3
V =555.65 m^3
Mass = 1.28 * 555.65
Mass = 711.23 kg

The volume of the basket = 0.064 m^3
The buoyant mass = the volume of air displaced * density
The buoyant mass = 0.064 m^3 * 1.28 kg/m^3 = 0.08192 kg

The buoyant mass is the difference between the balloon full of helium that displaces the air and the helium mass and the basket mass.
m =711.23 - 225.01+ 0.08192 = 486.30

The force = 486.30 * 9.81 = 4770.62 N

4) F person (no buoyancy) = 71 * 9.81 = 696.51 N
Buoyancy on each person = 0.08192

With buoyancy = 696.51 - 0.08192 * 1.28 * 9.81 =695.48 N
the actual force is close enough without the buoyancy, but I gave you both.

The number of people who could be lifted by the system = 4770.62/695.48 = 6.85 people. In this case you have to round downward, so you could lift 6 people.

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