A helicopter holding a 70-kilogram package suspended from arope 5.0 meters long

Question

A helicopter holding a 70-kilogram package suspended from arope 5.0 meters long accelerates upward at a rate of 5.2m/s2. Neglect air resistance on the package. b. Determine the tension in the rope c. When the upward velocity of the helicopter is 30 meters persecond, the rope is cut and the helicopter continues to accelerateupward at 5.3 m/s2. Determine the distance between thehelicopter and the package 2.0 seconds after the rope is cut. ***PLEASE HELP I HAVE NO IDEA HOW TO DO THIS!!!!!*** A helicopter holding a 70-kilogram package suspended from arope 5.0 meters long accelerates upward at a rate of 5.2m/s2. Neglect air resistance on the package. b. Determine the tension in the rope c. When the upward velocity of the helicopter is 30 meters persecond, the rope is cut and the helicopter continues to accelerateupward at 5.3 m/s2. Determine the distance between thehelicopter and the package 2.0 seconds after the rope is cut. ***PLEASE HELP I HAVE NO IDEA HOW TO DO THIS!!!!!***

Explanation / Answer

   mass of the package, m = 70 kg    length of the rope, l = 5m    acceleration of the helicopter, a = 5.2m/s^2 TENSION IN THEROPE:    Tension, T = m ( g + a ) = 70 ( 9.8 + 5.2 )= 1050 N DISTANCE:    initial velocity of helicopter,U1 = 30 m/s    distance travelled by helicopter in 2 s ,S1 = U1t + ( 1/2 ) a t 2                                                                   = 30 * 2 + 0.5 * 5.2 * 4                                                                   = 60 + 10.4                                                                   = 70.4 m ( Upward )    initial velocity of package, U2= -30 m/s    distance travelled by the package in 2 s ,S2 = U2 t - ( 1/2 ) g t 2                                                                      = -30 * 2 - 4.9 * 4                                                                      = -60 - 19.6 = - 79.6 m                                                                       =79.6 m ( downward)    distance between the helicopter and thepackage 2.0 seconds after the rope is cut , d = S1 +S2                                                                                                                                    = 150 m                                                                                                                                    = 150 m                                                           

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