You\'re standing 1.7 m horizontally from the edge of a 4.5 m -deep lake, with yo

Question

You're standing 1.7 m horizontally from the edge of a 4.5 m -deep lake, with your eyes 1.8 m above the water surface. A diver holding a flashlight at the lake bottom shines the light so you can see it.

Part A

If the light in the water makes a 44 angle with the vertical, at what horizontal distance is the diver from the edge of the lake?

Express your answer using two significant figures.

x= m

You're standing 1.7 m horizontally from the edge of a 4.5 m -deep lake, with your eyes 1.8 m above the water surface. A diver holding a flashlight at the lake bottom shines the light so you can see it.

Part A

If the light in the water makes a 44 angle with the vertical, at what horizontal distance is the diver from the edge of the lake?

Express your answer using two significant figures.

x= m

Explanation / Answer

given,

angle of incidence, theta_i = 44 degrees

let theta_r is the angle of refraction.

use Snell's law

sin(theta_i)/sin(theta_r) = n2/n1

sin(44)/sin(theta_r) = 1/1.33

sin(theta_r) = 1.33*sin(44)

= 0.92389

theta_r = sin^-1(0.92389)

= 67.5 degrees (angle made by the light with vertical in air)

horizontal distance between the diver and edge of the lake = 1.8*tan(67.5) + 4.5*tan(44) - 1.7

= 6.99 m <<<<<<<<------------Answer

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