How much heat is required to change a 36.8 g ice cube from ice at -14.9°C to wat

Question

How much heat is required to change a 36.8 g ice cube from ice at -14.9°C to water at 35°C? (if necessary, use cice=2090 J/kg°C and csteam= 2010 J/kg°C)
How much heat is required to change a 36.8 g ice cube from ice at -14.9°C to steam at 120°C?
How much heat is required to change a 36.8 g ice cube from ice at -14.9°C to water at 35°C? (if necessary, use cice=2090 J/kg°C and csteam= 2010 J/kg°C)
How much heat is required to change a 36.8 g ice cube from ice at -14.9°C to steam at 120°C?
How much heat is required to change a 36.8 g ice cube from ice at -14.9°C to water at 35°C? (if necessary, use cice=2090 J/kg°C and csteam= 2010 J/kg°C)
How much heat is required to change a 36.8 g ice cube from ice at -14.9°C to steam at 120°C?

Explanation / Answer

account for all the heat that is occurring
1. ice warms up from -14.9 degrees C to 0 degrees C
2. ice melts turning into liquid but remaining at 0 degrees C
3. water warms up to 35 degrees C

q1 = 36.8 g x 4.184 x (0-(-14.9))
q2 = 36.8 g x 2090
q3 = 36.8 g x 4.184 x (0-35)

qtotal = 2294.17088 + 76912 -5388.992
= 73817.178 J

2). same process as before
1. ice melts turning into liquid but remaining at 0 degrees c
2. water warms up from 0 to 120
3. water boils turning into steam but remaining at 120
qtotal = q1 + q2 + q3
q1 = 36.8 x 2090
q2 = 36.8 x 4.184 x (120-(-14.9))
q 3 = 36.8 x 2010
qtotal = q1 + q2 + q3
= 76912 + 20770.71488 + 73968
= 171650.715 J

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