Use the exact values you enter in previous answer(s) to make later calculation(s

Question

Use the exact values you enter in previous answer(s) to make later calculation(s).

A block of copper at a temperature of 54°C is placed in contact with a block of aluminum at a temperature of 40°C in an insulated container. As a result of a transfer of 1005 Jof energy from the copper to the aluminum, the final equilibrium temperature of the two blocks is 48°C.

(a) What is the approximate change in the entropy of the aluminum block?
J/K

(b) What is the approximate change in the entropy of the copper block?
J/K

(c) What is the approximate change in the entropy of the Universe?
J/K

(d) What is the change in the energy of the Universe?
J

Explanation / Answer

Entropy change,dS = Q/ T

Q= Energy transferred.

T = temperature

a) Entropy change in aluminum, dS = dQ/(273+40) ( positive Entropy change) ( low temperature)

dS = 1005/(273+40) = 3.2109 J/K.

b) Entropy change in copper, dS= -Q/(273+54)( Negative Entropy change)

dS= -1005/(273+54)

dS= -3.073 J/K.

c)Entropy change of the universe, dS= Q/Tavg.

dS = -1005/(273+48) = -3.1308 J/K.

d) Q =0

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