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Multiple Choice 1.) What does it mean if the amplitude of an object\'s vibration

ID: 1472826 • Letter: M

Question

Multiple Choice

1.) What does it mean if the amplitude of an object's vibration is constant and equal to 0.10 m?

     (a) The object's maximum distance from the starting point is 0.10 m.

     (b) The object's displacement from the equilibrium position is +,- 0.10 m.

     (c) The magnitude of the object's maximum displacement from the equilibrium position is 0.10 m.

2.) What is the period of the kinetic or the potential energy change if the period of position change of an object attached to a spring is 2.0 s?

     (a) The energy does not change

     (b) 4.0 s

     (c) 2.0 s

     (d) 1.0 s

3.) You have a simple harmonic oscillator. At what position(s) during simple harmonic motion is an oscillator's speed zero?

     (a) At the equilibrium position.

     (b) At the maximum distances form equilibrium.

     (c) At t=0

     (d) Because the oscillator is constantly moving, there is no place where its speed is zero.

4.) You have a simple harmonic oscillator. Where is the magnitude of its acceleration at its maximum?

     (a) At the equilibrium position.

     (b) At the maximum distances from equilibrium.

     (c) At t=0

     (d) The acceleration is constant.

Explanation / Answer

Here ,
1)

amplitude is the magnitude of maximum displacement of a oscillator

hence , it mean that

(c) The magnitude of the object's maximum displacement from the equilibrium position is 0.10 m.

2)

as the kinetic energy and potential energy reaches to maximum position 2 times in each cycle ,

the time period of kinetic energy and potential energy = time period of motion/2

the time period of kinetic energy and potential energy = 2/2

the time period of kinetic energy and potential energy = 1 s

the the time period of kinetic energy and potential energy is d) 1 s

3)

the speed of the oscillator is zero at the maximum position because all the energy is stored as potential energy at that point

hence , b) At the maximum distances form equilibrium.

4)

as acceleration is given as a = - w^2 * x

magnitude of acceleration is maximum when x is max

hence ,

the acceleration is maximum (b) At the maximum distances from equilibrium.