A pulse of light is created by the superposition of many waves that span the fre

Question

A pulse of light is created by the superposition of many waves that span the frequency range f012fff0+12f, where f0=c/ is called the center frequency of the pulse. Laser technology can generate a pulse of light that has a wavelength of 600 nm and lasts a mere 6.0 fs (1fs=1femtosecond=1015s).

A. What is the center frequency of this pulse of light?

B. How many cycles, or oscillations, of the light wave are completed during the 6.0 fs pulse?

C. What range of frequencies must be superimposed to create this pulse?

4.151014Hzf5.871014Hz

4.201014Hzf5.901014Hz

4.171014Hzf5.831014Hz

4.161014Hzf5.841014Hz

Explanation / Answer

A) center frequency is fo = c/lamda = (3*10^8)/(600*10^-9) = 5*10^14 Hz

B) in one cycle,it has 5*10^14 cycles

and so in 6 fs it has 6*10^-15*5*10^14 = 3 cycles

C) fo-(1/2)deltaf

deltaf = 1/deltaT = 1/(6*10^-15) = 1.66*10^14 Hz

0.5*deltaf = 0.83*10^14 Hz

then fo+(1/2)deltaf = (5+0.83)*10^14 = 5.83*10^14 Hz

f0-(1/2)deltaf = (5-0.83)*10^14 Hz = 4.17*10^14 Hz

So the answer is 4.171014Hzf5.831014Hz

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