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A Gymnast on a Rope A gymnast of mass 51.0 kg hangs from a vertical rope attache

ID: 1469904 • Letter: A

Question

A Gymnast on a Rope

A gymnast of mass 51.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume that the rope does not stretch. Use the value 9.81m/s2 for the acceleration of gravity.

Part A

Calculate the tension T in the rope if the gymnast hangs motionless on the rope.

Express your answer in newtons.

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Part B

Calculate the tension T in the rope if the gymnast climbs the rope at a constant rate.

Express your answer in newtons.

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Part C

Calculate the tension T in the rope if the gymnast climbs up the rope with an upward acceleration of magnitude 0.900 m/s2 .

Express your answer in newtons.

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Part D

Calculate the tension T in the rope if the gymnast slides down the rope with a downward acceleration of magnitude 0.900 m/s2 .

Express your answer in newtons.

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of 0

A Gymnast on a Rope

A gymnast of mass 51.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume that the rope does not stretch. Use the value 9.81m/s2 for the acceleration of gravity.

Part A

Calculate the tension T in the rope if the gymnast hangs motionless on the rope.

Express your answer in newtons.

SubmitHintsMy AnswersGive UpReview Part

Part B

Calculate the tension T in the rope if the gymnast climbs the rope at a constant rate.

Express your answer in newtons.

T = N

SubmitHintsMy AnswersGive UpReview Part

Part C

Calculate the tension T in the rope if the gymnast climbs up the rope with an upward acceleration of magnitude 0.900 m/s2 .

Express your answer in newtons.

T = N

SubmitHintsMy AnswersGive UpReview Part

Part D

Calculate the tension T in the rope if the gymnast slides down the rope with a downward acceleration of magnitude 0.900 m/s2 .

Express your answer in newtons.

T = N

SubmitHintsMy AnswersGive UpReview Part

Provide FeedbackContinue

T = N

of 0

Explanation / Answer

here,

mass of the gymnast , m = 51 kg

part A)

tension in the rope , T = m*g

T = 51 *9.8

T = 499.8 N

the tension in the rope is 499.8 N

part B)

as the rate is constant therefore zero accelration

tension in the rope , T = m*g

T = 51 *9.8

T = 499.8 N

the tension in the rope is 499.8 N

part C)

accelration , a = 0.9 m/s^2

tension in the rope , T = m*g + m*a

T = 51 *9.8 + 51*0.9

T = 545.7 N

the tension in the rope is 545.7 N

part D)

accelration , a = 0.9 m/s^2 downwards

tension in the rope , T = m*g - m*a

T = 51 *9.8 - 51*0.9

T = 453.9 N

the tension in the rope is 453.9 N

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