1. A group of students were being asked to verify the 0.300 kE relationships bet
ID: 1467962 • Letter: 1
Question
Explanation / Answer
a) The upward force acting on the spring is equal to magnitude of centripetal force.
Thus
Fs = Fc
k*x mv^2/r
Where k= spring constant
x= elongation in spring
m= mass of ball
v=velocity
r= radius
Plugging values of k,x,m and r we can find value of v
b)Use below figure,
c) By Newton’s second law
Fnet =ma
T=Fc = mv^2/r = 0.200*3.7^2/0.50 = 5.5 N
d) Percentage difference = [(actual value – calculate value)/ actual value]*100 = [(5.8-5.5)/5.8]*100 = 5.17%
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