A horizontal force is applied to a box that is initiall at rest on an inclined s
ID: 1467654 • Letter: A
Question
A horizontal force is applied to a box that is initiall at rest on an inclined surface. The direction of the force is up an incline of 35 degrees and the force applied is 40 Newtons. The mass of the block is 18 kilograms. The surface of the incline has a coeffcient of static friction of .360 anda coeffcient of kinetic friction of .240. A. The normal force in this situation is? B.The force of static friction in this situation is? C. The force of kinetic friction in this situation is? D. The acceleration of the box in this situation is? Photo in comments. Couldn't get it to upload!
Explanation / Answer
A)
Normal force N = F*sin(35) + (m*g*cos(35))
N = 40*sin(35) + (18*9.81*cos(35))= 167.58N
B) static frictional force = mu_s*N = 0.36*167.58 = 60.33 N
C) kinetic frictional force fk = mu_k*N = 0.24*167.58 = 40.21 N
D) F*cos(35)-fk-m*g*sin(35) = m*a
accelaration a = [F*cos(35)-fk-m*g*sin(35)]/m
a = [40*cos(35)-40.21-(18*9.81*sin(35)]/18
a= -6.04 m/s^2
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