A woman of mass m = 53.4 kg sits on the left end of a seesaw—a plank of length L

Question

A woman of mass m = 53.4 kg sits on the left end of a seesaw—a plank of length L = 4.68 m, pivoted in the middle as shown in the figure. (a) First compute the torques on the seesaw about an axis that passes through the pivot point. Where should a man of mass M = 67.3 kg sit if the system (seesaw plus man and woman) is to be balanced? 1.8567 Correct: Your answer is correct. m (b) Find the normal force exerted by the pivot if the plank has a mass of mpl = 12.2 kg. 1302.42 Correct: Your answer is correct. N (c) Repeat part (a), but this time compute the torques about an axis through the left end of the plank.

I got A and B correct, but we haven't covered part C in class or anything. Can someone please help me with this part? Please show your formulas and work. Thank you in advance.

Explanation / Answer

part C :

sum torques about left end

1302.42*4.68/2 - 12.2*9.81*4.68/2 - 67.3 *9.81*x =0

x = 4.2 m

if it is from middle

then 4.2 -( 4.68/2)

x = 1.86 m

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