005 10.0 points A uniform electric ficld of magnitude 5.89 x 105 V/m throughout

Q: 005 10.0 points A uniform electric ficld of magnitude 5.89 x 105 V/m throughout

005) Apply, electrical energy density = magnetic energy density (1/2)*epsilon*E^2 = B^2/(2*mue) ==> B^2 = E^2*epsilon*mue B^2 = E^2/c^2 (since, epsilon*mue = 1/c^2) B = E/c = 5.89*10^5/(3*10^8) = 1.96*10^-3 T 006) self inductance of solenoid, L = mue*N^2*A/l = 4*pi*10^-7*200^2*(pi*0.03^2/4)/0.82 = 4.33*10^-5 H = 43.3 micro H

ID: 1462084 • Letter: 0

Question

005 10.0 points A uniform electric ficld of magnitude 5.89 x 105 V/m throughout a cylindrical volume re- sults in a total energy of 3.62 . What magnetic field over this same region stores the same total energy? Answer in units of T 006 (part 1 of 4) 10.0 points An air-core solenoid consists of 200 turns of wire wounid on a form that is 82 cm long and has n inlier diameter ul. 3 cm The permcability of free spnee is /4-der x 10 1m/A Il n eurrett of 15 A is estabtished in this solenoid, wlmt is its self-inductat Answer ln mitsol ml

Explanation / Answer

005)

Apply, electrical energy density = magnetic energy density

(1/2)*epsilon*E^2 = B^2/(2*mue)

==> B^2 = E^2*epsilon*mue

B^2 = E^2/c^2 (since, epsilon*mue = 1/c^2)

B = E/c

= 5.89*10^5/(3*10^8)

= 1.96*10^-3 T

006)

self inductance of solenoid, L = mue*N^2*A/l

= 4*pi*10^-7*200^2*(pi*0.03^2/4)/0.82

= 4.33*10^-5 H

= 43.3 micro H

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005 10.0 points A uniform electric ficld of magnitude 5.89 x 105 V/m throughout

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