1) Consider a force F =80N applied to a beam as shown in the figure below. The l

Question

1) Consider a force F=80N applied to a beam as shown in the figure below. The length of the beam is=5.0m, and =37, so that x=3.0m andy=4.0m.
(Figure 1)

Of the following expressions, which ONES give the correct torque produced by the force  around point ?

2) A small solid sphere and a small thin hoop are rolling along a horizontal surface with the same translational speed when they encounter a 20 rising slope.

If these two objects roll up the slope without slipping, which will rise farther up the slope?

Thanks!!

(80 N)(4.0 m). (48 N)(5.0 m)(sin 37). (80 N)(5.0 m)(sin 37)). (80 N)(3.0 m). 80 N . (80 N)(5.0 m). (48 N)(5.0 m).

Explanation / Answer

1)

Torque is given as

80 x 4

(80 N)(5.0 m)(sin 37)).

2)

for each , Using conservation of energy

translational KE + Rotational KE = potential energy

(0.5) mV2 + (0.5) I W2 = mgh

for sphere , I = 2/5 mr2

(0.5) mV2 + (0.5) (0.4 mr2) (V/r)2 = mgh

(0.5) mV2 + (0.2) mV2 = mgh

h = 0.7V2 /g

for hoop , I = mr2

(0.5) mV2 + (0.5) (mr2) (V/r)2 = mgh

(0.5) mV2 + (0.5) mV2 = mgh

h = V2 /g

hence hoop goes higher

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