A converging lens, of focal length 192 mm has an object placed 384 mm in front o

Question

A converging lens, of focal length 192 mm has an object placed 384 mm in front of it. The image is 384 mm behind the lens (real image) 576 mm behind the lens (real image) 192 mm in front of the lens (virtual image) 192 mm behind the lens (real image) 384 mm in front of the lens (virtual image) The object is now moved to a new position 96 mm in front of the lens. The image is now located 96 mm in front of the lens (virtual image) 192 mm behind the lens(real image) 192 mm in front of the lens (virtual image) 288 mm in front of the lens (virtual image) 96 mm behind the lens (real image) The image of the object is 2x smaller than the object and inverted 2x smaller than the object and upright inverted but unchanged in size Magnified by 2x and upright Magnified by 2x and inverted

Explanation / Answer

fromlens equation

1/s + 1/s' = 1/f

s = object distance = 384 mm

s' = image distance = ?

f = focal length = 192 mm

1/384 + 1/s' = 1/192

s' = 384 mm

s' = positive

image is real

384mm behind the lens (real image) <<<-------answer

+++++++++++++++++++++++++

fromlens equation

1/s + 1/s' = 1/f

s = object distance = 96 mm

s' = image distance = ?

f = focal length = 192 mm

1/96 + 1/s' = 1/192

s' = -192 mm

s' = negative

image is virtual

192mm infront of the lens (virtual image) <<<-------answer

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