a centimeter ruler, balanced at its center point, has two coins placed on it. as

Question

a centimeter ruler, balanced at its center point, has two coins placed on it. as shown in the figure( figure 1) one coin of mass M1= 10g, is placed ar the zero mark; the other of unknown mass M2 is placed at 4.7cm mark. the center of the ruler is at the 3.0cm mark. the ruler is in equllibrium; it is perfectly balanced.     part A- does pivot point (i.e. the gin the diagram un which the ler balances) exert a force on the ruler?does it exert a nonzerotorque about the pivot?(yes or no answer)           part C- find the mass M2?           

Explanation / Answer

Part A: The pivot point exert force on the ruler . Yes

Yes, net torque is zero.

Net torque about an axis passing through pivot is zero.

Torque = rxF

M1 =10g, r1 = 3 cm , r2 = 4.7-3 =1.7 cm

r1*M1*g = r2*M2*g

(3*10) = 1.7*M2

M2 = 17.65 g

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