a capacitor C = 0.45 and a resistor R = 600 ohms are connected in a series. The

Question

a capacitor C = 0.45 and a resistor R = 600 ohms are connected in a series. The series combination is connected to an AC sine wave source with a frequency f = 400 Hz and an Rms-potential V = 240 V. Determine the impedance for the circuit. Calculate the rms-current for the circuit and the phase angle between the current and the total voltage Vrc. a capacitor C = 0.45 and a resistor R = 600 ohms are connected in a series. The series combination is connected to an AC sine wave source with a frequency f = 400 Hz and an Rms-potential V = 240 V. Determine the impedance for the circuit. Calculate the rms-current for the circuit and the phase angle between the current and the total voltage Vrc. a capacitor C = 0.45 and a resistor R = 600 ohms are connected in a series. The series combination is connected to an AC sine wave source with a frequency f = 400 Hz and an Rms-potential V = 240 V. Determine the impedance for the circuit. Calculate the rms-current for the circuit and the phase angle between the current and the total voltage Vrc.

Explanation / Answer

Capacitive inductance, Xc = 1 / (2 pi f C)

C = 0.45 uF = 0.45 x 10^-6 F

Xc = 1 / (2 x pi x 400 x 0.45 x 10^-6 ) = 884.2 ohm

Z = R - jXc = 600 - j 884.2 ohm

|Z| = sqrt[ R^2 + Xc^2] = 1068.55 ohm ................Ans

Irms = Vrms / |Z| = 240 / 1068.55 = 0.225 A .........Ans

phase angle = tan^-1(- Xc / R )   = tan^-1(-884.2 / 600) = - 55.84 deg

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