A square loop of wire with N turns is growing in a constant uniform magnetic fie

Question

A square loop of wire with N turns is growing in a constant uniform magnetic field, B, as shown below. The length of one of the sides of the square, ?(t), is increasing with time as the function ?(t) = ?t2 . Calculate the emf as a function of time.

A square loop of wire with N turns is growing in a constant uniform magnetic field, B, as shown below The length of one of the sides of the square, l(t), is increasing with time as the function 1(t) = t2 Calculate the emf as a function of time Earlier Time loop Select One of the Following bl em Later Time d) em (f) Toby

Explanation / Answer

The normal of the loop is the parallel to the field and field is uniform so Q= flux=NBA

Area=(l(t))2=(yt2)2

Q=flux=NB(yt2)2

emf=|-dQ//dt|=|4NBy2t3|

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