Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

PLEASE HELP! I have tried all these possible ans. and none are correct so far: (

ID: 1453497 • Letter: P

Question

PLEASE HELP! I have tried all these possible ans. and none are correct so far: (i have one try left)

0.031

0031

0041

0,041

When a person inhales, air moves down the bronchus (windpipe) at 15 cm/s. The average flow speed of the air doubles through a constriction in the bronchus. Assuming incompressible flow, determine the pressure drop in the constriction. (Enter the magnitude.) 0.041 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. Pa

Explanation / Answer

The pressure drop across the pipe is,

    P2 - P1 = (0.5)*density*velocity^2

    P2 - P1 = (0.5)*1.29*0.15^2

    P2 - P1 = 0.0145 Pa

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote