PLEASE HELP! I have tried all these possible ans. and none are correct so far: (
ID: 1453497 • Letter: P
Question
PLEASE HELP! I have tried all these possible ans. and none are correct so far: (i have one try left)
0.031
0031
0041
0,041
When a person inhales, air moves down the bronchus (windpipe) at 15 cm/s. The average flow speed of the air doubles through a constriction in the bronchus. Assuming incompressible flow, determine the pressure drop in the constriction. (Enter the magnitude.) 0.041 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. PaExplanation / Answer
The pressure drop across the pipe is,
P2 - P1 = (0.5)*density*velocity^2
P2 - P1 = (0.5)*1.29*0.15^2
P2 - P1 = 0.0145 Pa
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