Two ice pucks (one orange and one blue) of equal mass are involved in a perfectl

Question

Two ice pucks (one orange and one blue) of equal mass are involved in a perfectly elastic glancing collision as shown in the figure below. The orange puck is initially moving to the right at

voi = 7.85 m/s,

strikes the initially stationary blue puck, and moves off in a direction that makes an angle of

= 39.0°

with the horizontal axis while the blue puck makes an angle of

= 51.0°

with this axis as in figure (b). Note that for an elastic collision of two equal masses, the separation angle

+ = 90.0°.

Determine the speed of each puck after the collision.

v0f

vbf

v0f

vbf

Explanation / Answer

voi = 7.85 m/s. vbi = 0,

m1 =m2

vofx = vofcos(39) = 0.777vof

vofy = vofsin(39) =0.63vof

vbfx = vbfcos(51) = 0.63vbf

vbfy = vbfsin(51) = - 0.777vbf

From conservation of momentum along x direction

m1voix +m2vbix = m1vofx +m2vbfx

7.85+0 = (0.777vof) +(0.63vbf) ... (1)

From conservation of momentum along y direction

m1voiy +m2vbiy = m1vofy +m2vbfy

0+0 = (0.63vof) -(0.777vbf) ... (2)

by solving(1) and (2) we get

vof = 6.096 m/s

vbf = 4.94 m/s

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