The current in the battery is equal to The potential difference across the 3.00
ID: 1448520 • Letter: T
Question
The current in the battery is equal to
The potential difference across the 3.00 k?? resistor is equal to
The potential difference across the 2.00 k?? resistor is equal to
The potential difference across the 10.0 k?? resistor is equal to
The potential difference across the 20.0 k?? resistor is equal to
The potential difference across the 15.0 k?? resistor is equal to
The current in the 20.0 k?? resistor is equal to
The current in the 10.0 k?? resistor is equal to
The current in the 15.0 k?? resistor is equal to
The power dissipated in the 20.0 k?? resistor is equal to
Please show ALL work. Thank You!
Consider the resistive network shown below R1 (2.00 k2) R3 (10.0 ) 30.0 V (15.0 kQ) 4 (20.0 kQ) VM R5 (3.00 k2)Explanation / Answer
10 and 20 are in series which are in turn parallel wih 15 Kohm
their equivalent resisatnce be R'
R' = (10+20)||15
= 30||15
= 30*15/(30+15)
= 10 Kohm
This 10 Kohm is in series with 2 and 3 Kohm
I through 2 Kohm = I through 3Kohm = I though R'
= 30 /(10+2+3)
= 2 mA
V across 3 Kohm = 2 mA*3 Kohm = 6 V
V across 2 Kohm = 2 mA*2 Kohm = 4 V
V across 15 Kohm = V across series combination of R3 and R4 = 2 mA*R' =2mA*10 Kohm =20 V
V across series combination of 10 and 20 kohm = 20 V
I in 10 KOhm = I in 20 KOhm = 20/ (10+20 ) =0.67 mA
V across 10 KOhm = 0.67 mA*10 kohm = 6.7 V
V across 20 KOhm = 0.67 mA*20 Kohm =13.3 V
I in 15 Kohm = 20 V/15=1.33 mA
P in 20 Kohm = V*I = 13.3 V*0.67mA = 0.87 W
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