The current in the R 1 = 14.2 ohms resistor in the figure below is 0.708 A. Calc

Question

The current in the R1 = 14.2 ohms resistor in the figure below is 0.708 A.

Calculate the current in the R2 = 17.4 ohms resistor. Calculate the current in the R5= 8.70 ohms resistor. Calculate the current in the R6 = 4.04 ohms resistor. Calculate the current in the R3 = 15.7 ohms resistor. Calculate the current in the R4= 10.7 ohms resistor.

The current in the R1 = 14.2 ohms resistor in the figure below is 0.708 A. Calculate the current in the R2 = 17.4 ohms resistor. Calculate the current in the R5= 8.70 ohms resistor. Calculate the current in the R6 = 4.04 ohms resistor. Calculate the current in the R3 = 15.7 ohms resistor. Calculate the current in the R4= 10.7 ohms resistor.

Explanation / Answer

R1 and R2 in parallel

so the voltage across R1 and R2 is same

V1 = i1*R1 = 0.708*14.2 = 10.0536 V

V2 = V1 = 10.0536

V2 = i2*R2

i2 = V2/R2 = 10.0536/17.4 = 0.5778 A

R5 and R6 are in series

combination of R5 and R6 is in parallel with R1 and R2 so the voltage across the combination of R5 and R6 is 10.0536 V

R5 and R6 in series

total resistance = 8.7 + 4.04 = 12.74 ohm

current through R5 and R6 is same as they are in series

i5 = i6 = V/total resistance

i5 = i6 = 10.0536 / 12.74 = 0.7891 A

current in R4 be i4

using kirchoffs junction law

i3 = i5 + (i1+i2)

i3 = 0.7891 + ( 0.5778 + 0.708 )

i3 = 2.055 A

R3 and R4 are in series so i3=i4

i4 = i3 = 2.055 A

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