A battery with a non-negligible internal resistance has an EMF of 6V. A light bu

Question

A battery with a non-negligible internal resistance has an EMF of 6V. A light bulb with resistance R1 is connected across it's terminals. If you connect a 2nd resistor R2 to the circuit, which statement best describes what will happen?

A) the light bulb's brightness will dim if you connect R2 in parallel with bulb R1, and the SMALLER R2 the more it will dim.

B) the light bulb's brightness will dim if you connect R2 in parallel with bulb R1, and the LARGER R2 the more it will dim.

I've limited it down to these two options, shouldn't the lower R2 is the more current that will be able to go through it so it will be brighter. Or is the one with more resistance able to draw more current?

Explanation / Answer

the R2 connected in parallel than brightness will increase .

because in parallel equivalent resistance is less than the lesser value of individual resistance .

if R2 is lower than more current in bulb .

larger R2 will dim

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