A long, straight wire carries a current of 8.60 A. An electron is traveling in t

Question

A long, straight wire carries a current of 8.60 A. An electron is traveling in the vicinity of the wire.

A) At the instant when the electron is 4.30 cm from the wire and traveling with a speed of 5.90×104 m/s directly toward the wire, what is the magnitude of the force that the magnetic field of the current exerts on the electron?

B) What is the direction of this force? (Choose one of three and explain why)

1. the same as the direction of the current 2. perpendicular to the direction of the current 3. opposite to the direction of the current

Explanation / Answer

a)   B = µI/(2d) = (2*10^-7*8.6)/0.043 = 4*10^-5 T
As per the Lorentz force , F = qv X B
When F is perpendicular to B, F = qvB = 3.78*10^-19 N

b)  The direction of force is  the same as the direction of the current from lorentz force.

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