A long, straight wire carries a current of I 1 = 21.2 A as shown in the figure.

Question

A long, straight wire carries a current of I1 = 21.2 A as shown in the figure. A rectangular coil with two sides parallel to the straight wire has sides 5 cm and 10 cm with the near side a distance 2 cm from the wire. The coil carries a current of I2 = 3.70 A.

(a) Find the force on each segment of the rectangular coil due to the current in the long, straight wire.

top segment

N  --

Direction --- Up? down? left? right?

Left segment

N  --

Direction-- Up? down? left? right?

Bottom segment

N ---

Direction Up? down? left? right?

Right segment

N  --

Direction-- up ? down? left ? right ?

right segment
N  --

Direction-- up down left right

(b) What is the net force on the coil?

N  --

Direction-- up ?down ?left ?right?

Explanation / Answer

As force is given as F=I(Lx B)=IBLsin theta

Now the sides of rectangle(left segment and right segment) parallel to wire gives theta=0

Therefore F=0

Now Force on remaining sides of rectangle(top and bottom segment) is given as F=I2*B*L

I2*(mu_noght*I1/2pi*r)*L = 3.70*(4pi*1e-7*21.2/2pi*0.02)*0.05=3.92e-5 N

In top segment Ft=3.92e-5 N, down

In bottom segment, Fb=3.92e-5 N, up

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