In this example we will find the position and magnification of an image formed b
ID: 1444208 • Letter: I
Question
In this example we will find the position and magnification of an image formed by a spherical mirror. A lamp is placed 10 cm in front of a concave spherical mirror that forms an image of the filament on a screen placed 3.0 m from the mirror. What is the radius of curvature of the mirror? What is the lateral magnification? If the lamp filament is 5.0 mm high, how tall is its image?
A concave mirror has a radius of curvature R=25cm . An object of height 5 cm is placed 15 cm in front of the mirror. What is the image distance?Express your answers in centimeters to two significant figures.
Explanation / Answer
By mirror formula,
1/u + 1/v =1/f
-1/0.10 -1/3 . =1/f
1/f= -(30 +1)/3
f= -3/31
radius of curvature = 6/31 m =19 cm
magnification= -3/0.10= -30
Height of image=-30×5mm = -15 cm
hence image is 15 cm high and inverted
1/u + 1/v=1/f
-1/15 + 1/v = -2/25
1/v =1/15. - 2/25 = (5-6)/75
v= -75 cm
Image distance is 75 cm on the same side as the object
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.