A -4.70 C charge is moving at a constant speed of 6.80×105 m/s in the +xdirectio

Question

A -4.70 C charge is moving at a constant speed of 6.80×105 m/s in the +xdirection relative to a reference frame. At the instant when the point charge is at the origin, what is the magnetic-field vector it produces at the following points. (I tried using (4piE-7(-4.7E-6)(3.4E5))/4pi(sqrt.5^2)^3 and got 1.26E-5 and thought that is was the right way and apparently not so any help would be greatly appreciated!!)

Part A

x=0.500m,y=0, z=0

Enter your answers numerically separated by commas.

0,0,0

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Correct

Part B

x=0, y=0.500m, z=0

Enter your answers numerically separated by commas.

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Incorrect; Try Again; 4 attempts remaining

Part C

x=0.500m, y=0.500m, z=0

Enter your answers numerically separated by commas.

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Part D

x=0, y=0, z=0.500m

Enter your answers numerically separated by commas.

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Incorrect; Try Again; 5 attempts remaining

0,0,0

Explanation / Answer

a) Magentic field is vector a vector quantity.

so Field vector, B = (u0 q / 4 pi ) ( v x r ) / |r|^3

(v x r :-> this is the cross product of v and r )

v = 6.80E+5 i

r = 0.500 i + 0j + 0k

|r| = sqrt(0.5^2 + 0^2 + 0^2) = 0.5 m

B = (4pi x 10^-7 x -4.7 x 10^-6 / 4 pi) ( (6.80E+5 i ) X ( 0.500 i + 0j + 0k )) / 0.5^3

i x i = 0

B = 0

Ans(0, 0 , 0) T

b)
r = 0 i + 0.5j + 0k

|r| = sqrt(0^2 + 0.5^2 + 0^2) = 0.5 m

B = (4pi x 10^-7 x -4.7 x 10^-6 / 4 pi) ( (6.80E+5 i ) X ( 0 i + 0.5j + 0k )) / 0.5^3

B = - 1.278 E-6 T k Or -1.278 x 10^-6 k

Ans(0, 0 , -1.278 x 10^-6) T

c) r = 0.5 i + 0.5j + 0k

|r| = sqrt(0.5^2 + 0.5^2 + 0^2) = 0.707 m

B = (4pi x 10^-7 x -4.7 x 10^-6 / 4 pi) ( (6.80E+5 i ) X ( 0.5 i + 0.5j + 0k )) / 0.707^3

B = -4.522 x 10^-7 k

Ans(0, 0 , -1.278 x 10^-7) T

d) r = 0 i + 0j + 0.5k

|r| = sqrt(0^2 + 0^2 + 0.5^2) = 0.5 m

B = (4pi x 10^-7 x -4.7 x 10^-6 / 4 pi) ( (6.80E+5 i ) X ( 0 i + 0j + 0.5k )) / 0.5^3

B = 1.278 x 10^-6 T j

Ans(0, 1.278 x 10^-6, 0 ) T

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