A +2.60 ?C point charge is sitting at the origin. Part A) What is the radial dis

Question

A +2.60 ?C point charge is sitting at the origin.

Part A) What is the radial distance between the 500 V equipotential surface and the 1000 V surface?

Part B) What is the distance between the 1000 V surface and the 1500 V surface?

Part C) Explain why the answers to Part A and Part B are not the same.

Fill in the blank below with one of the following answer choices: closer to, inverse, squared, farther away from

The decrease in spacing of the equipotentials as you move _____ the charge is due to the fact that the potential is proportional to the ______ distance, not the distance.

Explanation / Answer

Electric Potential

V = Kq/r

V = 9 x109 x2.6 x 10-6/r

V = 23.4 x 103/r

V1 = 500 V

V2 = 1000 V

V3 = 1500 V

V1 = 500 = 23.4 x 103/r1

r1 = 46.8 m

V2 = 1000 = 23.4 x 103/r2

r2 = 23.4 m

V3 = 1500 = 23.4x103/r3

r3 = 15.6 m

(A)

|r2 – r1| = |23.4 – 46.8| = 23.4

(B)

|r3 – r2| = |15.6 – 23.4| = 7.8

(C)

The electric potential is inversely proportional to the distance. (The electric potential is not a function of addition but it is a function of division). Hence the potential progresses geometrically rather than arithmetically

The decrease in spacing of the equipotentials as you move farther away from the charge is due to the fact that the potential is proportional to the inverse distance, not the distance.

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