A +2.3 mC charge is placed 35 cm away from a stationary -3.4 mC charge. What is

Question

A +2.3 mC charge is placed 35 cm away from a stationary -3.4 mC charge. What is the electrical potential? In a 15 Volt potential, a particle has a potential energy of -0.45 J. What is the particle's charge? A -1.5 mC charge is moving towards a stationary +6.8 mC charge. What is the change in potential energy as the particle moves from 75 cm away from the stationary charge to only 33 cm from the stationary charge? Did the potential energy increase or decrease? A +1.5 mC charged particle (m = 4.3 kg) is placed 1.2 m from a +4.4 mC stationary charge. If it starts from rest, how fast will the particle be traveling when it is 2.0 m away from the stationary charge A +2.7 mC charged particle (m = 1.5 kg) is shot with an initial velocity of 202 m/sec towards a +1.8 mC stationary charge. If the particle starts out 1.4 meters from the stationary charge, how close will it come to the charge before turning around and moving away? A proton (m = 1.7 times 10^-27 kg, q = +1.6 times 10^-19 C) is placed at edge of the positive plate of a 2.4 times 10^-6 F capacitor. If the capacitor holds 17 mC of charge on its positive plate, how fast will the proton be moving when it reaches the negative plate of the capacitor?

Explanation / Answer

Given that

charge q1=1.5mC

charge q2=4.4mC

distance r=1.2 m

seperation b/w the chargesa s=2 m

now we find the force of attraction b/w two charges

force of attraction F=9*10^9*1.5*4.4*10^-6/(1.2)^2=41.3*10^3 N

now we find the speed of the stationary charge is moving

1/2m(v^2-u^2)=F*s

1/2*4.3(v^2-0^2)=41.3*10^3*2

v^2=38418.6

speed V=196 m/s

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