A series AC circuit contains a resistor, an inductor of 230 mH, a capacitor of 4

Question

A series AC circuit contains a resistor, an inductor of 230 mH, a capacitor of 4.20 F, and a generator with Vmax = 240 V operating at 50.0 Hz. The maximum current in the circuit is 200 mA.

-i have A and B need help with C, D, and E

(a) Calculate the inductive reactance.

answer= 72.22

(b) Calculate the capacitive reactance.

answer= 758

(c) Calculate the impedance.

answer=_______k

(d) Calculate the resistance in the circuit.

answer=________k

(e) Calculate the phase angle between the current and the generator voltage.

answer=________°

Explanation / Answer

in series circuit maximum current ocurres at resonance condition

AT RESONANCE impedence is purely resistive , i = Imax = 200 mA

=> Imax = V/R

=> Resistance R = V/Imax = 240/(200*10^-3) = 1.2 kilo-ohm .........PART (d)

PART (c) impedence of the circuit

Z^2 = R^2 + (XL - XC)^2 = (1.2*10^3)^2 + (72.22 - 758)^2 = 1.44*10^6+ 470294.20 = 191*10^4

=> Z = 1.38 kilo-ohm

PART (e) phase angle between current and voltage

current will be leading voltage because XC > XL

tan(theta) = (XC - XL)/R = 685.78/1200 = 0.571

=> theta = 29.72 degree   

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