You are givem a 47 V battery and two resistors of resistances 25.5 ohms and 96 o

Question

You are givem a 47 V battery and two resistors of resistances 25.5 ohms and 96 ohms.

1.Find current in A when these resistors are connected in series with the battery.

2.Find the power dissipated in W by the 25.5 ohms resistor when connected in series with rest of the circuit.

3.Find the power dissipated in W by the 96 ohms resistor when connected in series with rest of the circuit.

4. Find the current in A being drawn from the battery when the resistors are connected in parallel with the battery.

Explanation / Answer

part 1 )

when connected in series

Req = R1 + R2 = 25.5 + 96 = 121.5 ohm

I = V/Req

I = 47/121.5

I = 0.3868 A

part 2)

P = I^2*R

in series current is same for every resistor

P at 25.5 ohm

P = 3.81578 W

part 3 )

P at 96 ohm

P = 14.65 W

part 4 )

in parallel equivalent resistance

1/Req = 1/R1 + 1/R2

Req = R1*R2/(R1+R2)

Req = 20.148 ohm

I = V/Req

I = 2.3327 A

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