You must complete the circuit of (Figure 1) in such a way that it draws a curren

Question

You must complete the circuit of (Figure 1) in such a way that it draws a current of 0.300 A from the battery. The battery maintains a potential difference of 10.0 V with no load, but has an internal resistance of Rbatt = 12.0 .The only material you have is 20.0 mm3 of nichrome, and you must use all of it. your plan is to form the nichrome into a cylindrical resistor. [The conductivity of nichrome is 6.7 × 105 A/(Vm).]   https://session.masteringphysics.com/problemAsset/1924742/3/Mazur1e.ch31.p58.jpg

Part A

What must the cylinder length be?

Part B

What must the cylinder cross-sectional area be?

Explanation / Answer

Here,

I = 0.3 A

potential difference , V = 10 V

Rbatt = 12 Ohm

let the length is L

cross sectional area is A

L * A = 20 *10^-9 ---(1)

for the external resistance

R + Rbatt = 10/.3

R + 12 = 33.3

R = 21.3 Ohm

as R = p * L/A

21.3 = 1/(6.7 *10^5) * L/A ----(2)

solving for L and A

L = 0.534 m

A = 3.74 *10^-8 m^2

part A)

the length of cyclinder is 0.534 m

part B)

the cross sectional area is 3.74 *10^-8 m^2

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