You must complete the circuit of (Figure 1) in such a way that it draws a curren

Question

You must complete the circuit of (Figure 1) in such a way that it draws a current of 0.300A from the battery. The battery maintains a potential difference of 10.0 V with no load, but has an internal resistance of Rbatt = 12.0? . The only material you have is 20.0 mm3 of nichrome, and you must use all of it. your plan is to form the nichrome into a cylindrical resistor. [The conductivity of nichrome is 6.7

You must complete the circuit of (Figure 1) in such a way that it draws a current of 0.300A from the battery. The battery maintains a potential difference of 10.0 V with no load, but has an internal resistance of Rbatt = 12.0? . The only material you have is 20.0 mm3 of nichrome, and you must use all of it. your plan is to form the nichrome into a cylindrical resistor. [The conductivity of nichrome is 6.7 105 A/(V?m).] A-What must the cylinder length be? B-What must the cylinder cross-sectional area be?

Explanation / Answer

To get 0.300A, the equivalent resistance must be

Req = V/I

= 33.33 ohm

As Req = Rbatt +Rload

-->Rload = Req - Rbatt

Rload = 21.33 ohm

As

Rload = (rho) L / A

and

Volume = A L

--> A = Volume / L

Thus,

Rload = (rho) L^2 / Volume

--> L = sqrt {[Rload Volume] / rho}

Hence,

L = 7.98E-7 m   [ANSWER, PART A]

As A = volume/L,

A = 0.0251 m^2   [ANSWER, PART B]

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.