A 53.0-cm wire is moving to the right at a speed of 8 30 m/s across two parallel

Question

A 53.0-cm wire is moving to the right at a speed of 8 30 m/s across two parallel wire rails that are connected on the left side, as shown in the figure The whole apparatus is immersed in a uniform magnetic field which has a magnitude of 0.790 T and is directed into the screen What is the emf induced in the wire? The induced emf causes a current to flow in the circuit formed by the moving wire and the rads In what direction does the current flow around the circuit ? If the moving wire and the rails have a combined total resistance of 1 55 O, what applied force would be required to keep the wire moving at the given velocity? Assume that there is no friction between the moving wire and the rails.

Explanation / Answer

a)

induced emf = vBL = 8.30*0.790*0.53 = 3.47 V

b)

counter clock wise   

incuced emf always opposes the changes

c)

current = E/R = 3.47/1.55 = 2.23 Amp

force = BIL = 0.790*2.23*0.53 = 0.9337 N

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