A microscope has an objective lens with f = 16.22 mm and an eyepiece with f = 9.

Question

A microscope has an objective lens with

f = 16.22 mm

and an eyepiece with

f = 9.6 mm.

With the length of the microscope's barrel set at 29.0 cm, the diameter of an erythrocyte's image subtends an angle of 14.3 mrad with the eye. If the final image distance is 27.0 cm from the eyepiece, what is the actual diameter of the erythrocyte? Hint: Start with the size of the final image then use the thin-lens formula for each lens to find their combined magnification. Use this magnification to calculate the object size in the final step.

Explanation / Answer

magnification m = (L/fo)*(1 + D/fe)

m = (290/16.22)*(1 + 270/9.6) = 521

m = size of the image /size of the object

521 = (27*1.43*10^-3)/size of the object

size of the object = 7.41*10^-5 m = 741 mm <<------answer

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