A 2.80 mu F capacitor is charged to 540 V and a 4.20 mu F capacitor is charged t

Question

A 2.80 mu F capacitor is charged to 540 V and a 4.20 mu F capacitor is charged to 650 V. These capacitors are then disconnected from their batteries, and the positive plates are now connected to each other and the negative plates are connected to each other. What will be the potential difference across each capacitor? 2.80 mu F capacitor 4.20 mu F capacitor What will be the charge on each capacitor? 2.80 mu F capacitor 4.20 mu F capacitor What is the voltage for each capacitor if plates of opposite signs are connected? 2.80 mu F capacitor 4.20 mu F capacitor What is the charge on each capacitor if plates of opposite signs are connected? 2.80 mu F capacitor 4.20 mu F capacitor

Explanation / Answer

a) charge on 2.80 uF = CV = 2.80 uF x 540 = 1512 uC

charge on 4.20 uF = 4.20uF x 650 V = 2730 uC

both capacitors are connected in parallel.

so potential difference across them will be equal say V.

and charge will be conserved.

initiall total charge = final charge

1512 + 2730 = 2.80V + 4.20V

V = 606 volt ........Ans for both capacitors.

charge on 2.80 uF capacitor:

Q = Cv = 2.80 x 606 = 1696.8 uC .....Ans

charge on 4.20 uF capacitor

Q = CV = 4.20 x 606 = 2545.2 uC ...Ans

Answer will be same you can join them in any order.
Until these capacitors are in circuit then answers will be same.

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