A 2.80 kg rock has a horizontal velocity of magnitude 12.0 m/s when it is as poi
ID: 1288182 • Letter: A
Question
A 2.80 kg rock has a horizontal velocity of magnitude 12.0 m/s when it is as point P in the figure.
A. At this instant, what is the magnitude of its angular momentum relative to point O?
B. What is the direction of the angular momentum in part (A)? (In or out of the page)
C. If the only force acting on the rock is its weight, what is the magnitude of the rate of the change of its angular momentum?
What is the direction of the rate in part (C)? (In or out of the page)
A 2.80 kg rock has a horizontal velocity of magnitude 12.0 m/s when it is as point P in the figure. A. At this instant, what is the magnitude of its angular momentum relative to point O? B. What is the direction of the angular momentum in part (A)? (In or out of the page) C. If the only force acting on the rock is its weight, what is the magnitude of the rate of the change of its angular momentum? What is the direction of the rate in part (C)? (In or out of the page)Explanation / Answer
A) L = r*P*sin(36.9)
= 8*2.8*12*sin(36.9)
= 161.4 kg.m/s
B) In to the page
C) dL/dt = Torque
= m*g*r*sin(90-36.9)
= 2.8*9.8*8*sin(53.1)
= 175.5 kg.m^2/s
d) out of the apge
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