18.Diagrams A and B show the electric potential along the x-axis in two differen

Question

18.Diagrams A and B show the electric potential along the x-axis in two different situations. Answer each of the questions below with True (T), False (F), or Can not tell (C). If, for example, the answer to the first question is True, the answer to the second is Can Not Tell, and the answer to the others is False, enter TCFFFF. The electric field at x = 2 m in Diag. A points to the left. The magnitude of the electric field at x = 4 m in Diag. A is larger than the magnitude of the electric field at x = 4 m in Diag. B. A positive charge placed at x = 4 m in Diag. A and released will accelerate right. The work done by you to bring a positive charge from infinity to the point x = 1 m in Diag. A is greater than zero. The electric potential at x = 3 m in Diag. A is larger than the electric potential at x = 2 m in Diag. B. An electric dipole with its positive charge at y = 0.01 mm and its negative charge at y = -0.01 mm placed at x = 4 m in Diag. A and released will initially rotate counterclockwise. Answer:

20. [1pt] Calculate the force on a positive charge of 1 µC located at the point x = 4 m in diagram A. (If the force is parallel to the ?x axis, then the force is negative.) Answer: Last Answer: 125V/m Not yet correct, tries 0/15

21. [1pt] Calculate the initial acceleration of a proton placed at the point x = 2 m in diagram B. (If the acceleration is parallel to the ?x axis, then the acceleration is negative.)

Explanation / Answer

(a) True

At x=2, potential gradiant i.e. slope is positive and electric field is negative of potential gradiant hence it wil be in -ve direction therefore in left hence true.

(b) True

Again the slope is higher in diagram A than in B at x=4 although they have opposite sign. Hence magnitude wil be higher but direction will be opposite.

(c) true.

As explained in part (a), the slope is negative hence field will be in +ve direction which means towards right hence positive charge will accelerate towards right.

(d) False

As the potential of point x=1 is positive and field is towards left direction whic means +ve charge will naturally moves from infinite to x=1 and we do not required to do do external work and hence it will be -ve

(e) True

Potential at point x=3 in dia A is 300 V while potential at x=2 in diagram B is -125 V hence true

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