(Be clear and concise. Typing work is strongly suggested. Will thumb up based on

Question

(Be clear and concise. Typing work is strongly suggested. Will thumb up based on the quality of the answer given.) What is the magnitude of the magnetic field at point P in the figure if a = 2.0 cm, b = 4.5 cm, and 1= 5.0 A? (Give your answer in micro Tesla: mu T) The figure shows a cross section of three parallel wires each carrying a current of 15 A. The currents in wires A and C are out of the paper, while that in wire B is into the paper. If the distance R = 5.0 mm, what is the magnitude of the force on a 4.0-m length of wire C? (Give your answer in mN, lmN=10^-3N)

Explanation / Answer

Here ,

1A)

for the magnitude of magnetic field at point P

magnetic field at P = u0 * I/2 * (1/a - 1/b)

magnetic field at P = 4pi * 10^-7 * 5/2 * (1/0.02 - 1/.045)

magnetic field at P = 8.73 *10^-5 T = 87.3 uT

the magnetic field at P is 87.3 uT

1B)

for the net force at C

FC = u0*I*I*L/(2pi) * (1/R - 1/(2R))

FC = 4pi *10^-7 * 15^2*4/(2pi) * (1/0.005 - 1/(2 * 0.005))

solving

FC = 0.0045*4 N

FC = 18 *10^-3 N

the magnitude of force acting 18 mN

the magnitude of force acting on wire C is 18 mN

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