(Be clear and concise. Typing work is strongly suggested. Will thumb up based on
ID: 1423828 • Letter: #
Question
(Be clear and concise. Typing work is strongly suggested. Will thumb up based on the quality of the answer given.) A planar loop consisting of four turns of wire, each of which encloses 200 cm^2, is oriented perpendicularly to a magnetic field that increases uniformly in magnitude from 10 mT to 25 mT in a time of 5.0 ms. What is the resulting induced current in the coil if the resistance of the coil is 5.0 Q? (Give your answer in mA) At what frequency should a 200-tum, flat coil of cross sectional area of 300 cm^2 be rotated in a uniform 30-mT magnetic field to have a maximum value of the induced emf equal to 8.0 V?Explanation / Answer
here,
1A)
area of the loop , a = 0.02 m^2
change in magnetic feild , delta B = 0.025 - 0.01 T = 0.015 T
time taken , t = 0.005 s
the induced emf , EMF = change in flux /time taken
EMF = a * delta B /delta t
EMF = 0.02 * 0.015 /0.005
EMF = 0.06 V
resistance , r = 5 ohm
induced current , I = EMF /r
I = 0.06/5 = 0.012 A
I = 12 mA
the resulting induced current is 12 mA
1B)
number of turns , n= 200
cross sectional area , a = 0.03 m^2
magnetic feild , B = 0.03 T
EMF = 8 V
let the frequency be f
EMF = 2 * pi * f * n * a * B
8 = 2 * pi * f * 200 * 0.03 * 0.03
f = 7.08 Hz
the frequency needed is 7.08 Hz
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.