(Be clear and concise. Typing work is strongly suggested. Will thumb up based on
ID: 1423779 • Letter: #
Question
(Be clear and concise. Typing work is strongly suggested. Will thumb up based on the quality of the answer given.) A charged particle (mass = 4.0 Mu g, charge = 5.0 Mu c) moves in a region where the only force on it is magnetic. What is the magnitude of the acceleration of the particle at a point where the speed of the particle is 5.0 km/s, the magnitude of the magnetic field is 8.0 mT, and the angle between the direction of the magnetic field and the velocity of the particle is 60 degree ? (Give your answer in km/s^2) A straight wire of length 70 cm carries a current of 50 A and makes an angle of 60 Degree with a uniform magnetic field. If the force on the wire is 1.0 N what is the magnitude of B? (Give your answer in mT. 1mT=10^ -3T)Explanation / Answer
1A) Magnatic force = qVXB = qVBsin(theta)
= 5*(10^-6)*5*8*(10^-3)sin(pi/3)
= 1.732*10^-4 N
=> accleration = F/M = 1.732*(10^-4)/(4*10^-9)
= 43300 m/s^2 = 43.3 km/s^2 Answer
1B) Force = current*lengthXmagnatic_field = current*length*magnatic_field*sin(theta)
=> magnatic field (B) = 1/(50*0.7*sin(pi/3)) = 32.99 mT Answer
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