A basket of negligible weight hangs from a vertical spring scale of force consta

Question

A basket of negligible weight hangs from a vertical spring scale of force constant 1500 N/m .
Part A
If you suddenly put a 3.00 kg adobe brick in the basket, find the maximum distance that the spring will stretch.

lmax =
0.02
  cm  

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Part B
If, instead, you release the brick from 1.00 m above the basket, by how much will the spring stretch at its maximum elongation?

l =
0.198
  cm  

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Explanation / Answer

a) m*g = k* x

3*10 = 1500* x

=> x = 0.02 m = 2 cm

b) but velocity of brick at the time contact = square root(2*g*h) = square root(2*10*1) = 4.472 m/s

so this becomes the initial velocity for SHM and hence solving for SHM,

we get amplitude A = initial velocity / square root (k/m) = 4.472 / square root(1500/3) = 0.2 m = 20 cm.

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