A milliammeter reads 30 mA full scale. It consists of a 0.15-Ohm resistor in par

Question

A milliammeter reads 30 mA full scale. It consists of a 0.15-Ohm resistor in parallel with a 33-Ohm galvanometer. How can you change this ammeter to a voltmeter giving a full-scale reading of 30 V without taking the ammeter apart? A resistor must be placed in parallel with the existing meter. A resistor must be placed in series with the existing meter. What is the of this resistor? Express your answer to two significant figures and include the appropriate units. What will be the sensitivity (Ohm/V) of your voltmeter? Express your answer using tow significant figures. 

Explanation / Answer

part A

the resistor must be placed in parallel connection with exiting ammeter because the voltage is passing in each resistor is same so does not take any current

part B

resistance R=[v/ig-G]=[30/30*10^-3-33]=967 ohms

part C

the sensitivity =967/33=29.3 ohms/V

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