Exercise 29.28 Part A A 1.60-m-long metal bar is pulled to the right at a steady

Question

Exercise 29.28 Part A A 1.60-m-long metal bar is pulled to the right at a steady 4.4 m/s perpendicular to a uniform, 0.720-T magnetic field. The bar rides on parallel metal rails connected through R -24.6-S2, as shown in the figure (Figure 1) so the apparatus makes a complete circuit. You can ignore the resistance of the bar and the rails. Calculate the magnitude of the emf induced in the circuit. Express your answer using two significant figures. Submit My Answers Give Up Figure 1 of 1 Part B Find the direction of the current induced in the circuit clockwise . counterclockwise Submit My Answers Give Up Correct

Explanation / Answer

The formula for induced emf is

e = d(t) / dt = B * l * v

=0.720(1.6)(4.4)

=5.06 V

(b)

According to Lenz's law emf generated opposes it's cause to oppose the cause the magnetic force due current must be in backward direction to decrease speed of the rod.

to satisfy this condition the current must be upwards in the rod, that is current must be counter-clockwise.

(c)

I = e/R = 5.0688 V/24.6 = 0.20 A

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