Exercise 26.37 Part A A circuit consists of a series combination of 5.50-kS2 and

Question

Exercise 26.37 Part A A circuit consists of a series combination of 5.50-kS2 and 4.50 -k2 resistors connected across a 50.0-V battery having negligible intemal resistance. You want to measure the true potential difference (that is, the potential difference without the meter present) across the 4.50 -k2 resistor using a voltmeter having an internal resistance of 10.0 k2. What potential difference does the voltmeter measure across the 4.50-k2 resistor? Submit My Answers Give Up Part B What is the true potential difference across this resistor when the meter is not present? Submit My Answers Give Up Part C By what percentage is the voltmeter reading in error from the true potential difference? %error- Submit My Answers Give Up

Explanation / Answer

A)

What potential difference does the voltmeter measure across the 4.50k resistor?

10k in parallel with 4.5k = 4.5*10/4.5+10 = 3103.45 ohms

the circuit is effectively 3.1k in series with 5.5k across 50v

voltage divider operation is 50* 3.1/(3.1+5.5) = 18.04Volts

B)

What is the true potential difference across this resistor when the meter is not present?

voltage divider action is 50*4.5/(4.5+5.5) = 22.5 Volts

C)

By what percentage is the voltmeter reading in error from the true potential difference?

(22.5 - 18.04)/22.5 = .198 = 19.8%

Hope this helps :)

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.