An electron in the solar wind enters Earth’s magnetic field moving at a speed of

Question

An electron in the solar wind enters Earth’s magnetic field moving at a speed of 200m/s. If the strength of Earth’s magnetic field is 2.0 x 10-5T, find the magnitude of the force on the electron. Assume the field and the velocity are 90 degrees apart An electron in the solar wind enters Earth’s magnetic field moving at a speed of 200m/s. If the strength of Earth’s magnetic field is 2.0 x 10-5T, find the magnitude of the force on the electron. Assume the field and the velocity are 90 degrees apart 6.4 x 10-22 N 0.04 N 32.4 N none of the above 9 x 10-6 N

Explanation / Answer

Magnetidue of force acting on the electron,

F = q*v*B*sin(theta)

= q*v*B* sin(90)

= q*v*B

= 1.6*10^-19*200*2*10^-5

F= 6.4*106-22 N

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