A mass weighing 4 pounds is attached to a spring whose constant is 2 lb/ft. The

Question

A mass weighing 4 pounds is attached to a spring whose constant is 2 lb/ft. The medium offers a damping force that is numerically equal to the instantaneous velocity. The mass is initially released from a point 1 foot above the equilibrium position with a downward velocity of 6 ft/s. Determine the time at which the mass passes through the equilibrium position. (Use

g = 32 ft/s2

for the acceleration due to gravity.)

(MISSING)

s

Find the time after the mass passes through the equilibrium position at which the mass attains its extreme displacement from the equilibrium position.

(MISSING) s

What is the position of the mass at this instant?

(MISSING)

ft

solve the MISSING pleeasse help

Explanation / Answer

a. apply the kinematic equation V^2 -u^2 = 2gs

where v is final velocity

and u is initail velocity

s = distance = 1 ft

so

v^2-6^2   = 2* 32 * 1

V^2 = 64+ 36

v = 10 ft/s

------------------------------

appla = v/t

time t = v/a = 10/32

t = 0.3125 secs

-------------------------------

S = So + ut   + 0.5 gt^2

S = 1 ft + ( 2 * 0.3125) + (0.5* 32* 0.3125 * 0.3125)

S = 3.1875 ft

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.